6x^(2/3)-17x^(1/3)-3=0

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Solution for 6x^(2/3)-17x^(1/3)-3=0 equation: 


x in (-oo:+oo)

6*x^(2/3)-(17*x^(1/3))-3 = 0

6*x^(2/3)-17*x^(1/3)-3 = 0

t_1 = x^(1/3)

6*t_1^2-17*t_1^1-3 = 0

6*t_1^2-17*t_1-3 = 0

DELTA = (-17)^2-(-3*4*6)

DELTA = 361

DELTA > 0

t_1 = (361^(1/2)+17)/(2*6) or t_1 = (17-361^(1/2))/(2*6)

t_1 = 3 or t_1 = -1/6

t_1 = -1/6

x^(1/3)+1/6 = 0

1*x^(1/3) = -1/6 // : 1

x^(1/3) = -1/6

( -1/6 < 0 i 1/3 in (0:1) ) => x należy do O

t_1 = 3

x^(1/3)-3 = 0

1*x^(1/3) = 3 // : 1

x^(1/3) = 3

x^(1/3) = 3 // ^ 3

x = 27

x = 27

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